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    The answer is
    5 - 1 where did I mess up?
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    (Original post by ckfeister)
    Name:  question1.jpg
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Size:  175.3 KBAttachment 727182727184

    The answer is
    5 - 1 where did I mess up?
    first line, you would have to raise e to the power of the whole left hand side.
    It would be easier to first combine the two ln functions using the rule ln(a) + ln(b) = ln(ab)
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    Use the log properties to combine them:

    ln(x+3) + ln(x-1) = 0

    Hence, ln[(x+3)(x-1)] = 0

    Can you continue it?
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    When you're applying something to an equation, e.g. adding a number, multiplying, dividing, any functions (taking ln, integrating, raising e to both sides, etc etc), you must do it to all of LHS and all of RHS respectively (not to each term).
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    (Original post by thekidwhogames)
    Use the log properties to combine them:

    ln(x+3) + ln(x-1) = 0

    Hence, ln[(x+3)(x-1)] = 0
    You know not to post full solutions - please edit your post.
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    (Original post by Muttley79)
    You know not to post full solutions - please edit your post.
    Ah sorry my bad, edited. But the answer was already provided and it was a showing question.
 
 
 
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