Solve the equation 2 sin 3x=1 for -360<x<360 They got the answers x = −350°, −310°, −230°, −190°, −110°, −70°, 10°, 50°, 130°, 170°, 250°, 290°. I will post my working... I got half the answers but I don't how they got the rest.
Even though the range is from -360 to 360 for x, 3x can be higher than that while still being positive. So they found all the possible positive values for sin3x and then divided them all by 3 after the arcsin, then they fell within this range
Even though the range is from -360 to 360 for x, 3x can be higher than that while still being positive. So they found all the possible positive values for sin3x and then divided them all by 3 after the arcsin, then they fell within this range
the ones I've underlined in red, when divided by 3 they aren't right, I don't know why because i followed the rules of the quadrants properly. Same with the minuses, I haven't posted that part put if you guys can tell me where I have gone wrong, then i will apply that to th minus part
the ones I've underlined in red, when divided by 3 they aren't right, I don't know why because i followed the rules of the quadrants properly. Same with the minuses, I haven't posted that part put if you guys can tell me where I have gone wrong, then i will apply that to th minus part
Can you please explain how you used the quadrant diagram to get 330?
Can you please explain how you used the quadrant diagram to get 330?
sin(330) is not 1/2.
360-30 because its another revolution you add 180 degrees to 180 making 360 degrees. See in my working out, I do not get how that doesn't give you 1/2?
360-30 because its another revolution you add 180 degrees to 180 making 360 degrees. See in my working out, I do not get how that doesn't give you 1/2?
Do you know CAST? How have you taught to use the quadrant diagram?
For another revolution you need to add 360. So to get to that line in the first quadrant a second time you have to go all the way around anticlockwise (360) and then reach the line (+30) which gives you 360 + 30 = 390.