2-Methylpropan-1-ol can also be converted to produce diesel and jet fuel.
The first step in the process is the production of 2-methylpropene.
C4H10O(l) → C4H8(g) + H2O(g)
C4H10O(l) is 2-methylpropan-1-ol
C4H8(g) is 2-methylpropene
Using the data below, calculate the enthalpy change, in kJ mol-1, for the production of 2-methylpropene from 2-methylpropan-1-ol.
4C(s) + 5H2(g) + ½O2(g) → C4H10O(l) ΔH = -335 kJ mol-1
4C(s) + 4H2(g) → C4H8(g) ΔH = -17 kJ mol-1
H2(g) + ½O2(g) → H2O(g) ΔH = -242 kJ mol-1 (would this be combustion so the arrow would be facing down?)
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How would you do this using the Hess Law diagram? watch
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