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    How do you figure the upper and lower bounds of 7.6?
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    Usually there is a unit/significant figure to work by but in this case i'll assume its to 1 d.p
    0.1÷2= 0.05
    7.6+/- 0.05
    7.6 to nearest tenths = 7.55 & 7.65
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    (Original post by chili_180)
    How do you figure the upper and lower bounds of 7.6?
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    they have started calling them "error intervals" for the new exams....

    so your error interval would be written as

    7.55≤ L <7.65

    if the measurement was L for length for instance.
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    thanks
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    (Original post by Gaxia_zoom)
    Usually there is a unit/significant figure to work by but in this case i'll assume its to 1 d.p
    0.1÷2= 0.05
    7.6+/- 0.05
    7.6 to nearest tenths = 7.55 & 7.65
    Dat's right!
 
 
 

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