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    How would you find the turning point of a quadratic graph when you are only given the y intercept(0,-10) and the coordinate of one intersection on the x axis (5,0)? Any help would be really appreciated.
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    Do you know the exact question? Like, if you can assume a=1 in ax^2 + bx + c ?
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    (Original post by Mehru1214)
    Do you know the exact question? Like, if you can assume a=1 in ax^2 + bx + c ?
    Yes in the actual question the coefficient of x^2 is 1
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    (Original post by gdunne42)
    Yes in the actual question the coefficient of x^2 is 1
    Ok, gimme a few mins, I can figure it out!
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    (Original post by Mehru1214)
    Ok, gimme a few mins, I can figure it out!
    I know the answer from the mark scheme I think it's 1.5 just don't have any idea how to do it
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    (Original post by Dan_Jenkins)
    I know the answer from the mark scheme I think it's 1.5 just don't have any idea how to do it
    Ok, so here's my way of doing it, using what I was taught. I'm a grade 9 student, so I know it's right, just may be a little hard to understand. Hopefull you can read it!
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    (Original post by Mehru1214)
    Ok, so here's my way of doing it, using what I was taught. I'm a grade 9 student, so I know it's right, just may be a littl hard to understand. Hopefull you can read it!
    Omg thnx so much you've really helped Your the best hahaha
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    (Original post by Dan_Jenkins)
    Omg thnx so much you've really helped Your the best hahaha
    No problem! Always happy to help!
 
 
 
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