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# Can you check my answers please? watch

1. It looks ok but the last question I think is wrong since you just added one side of each length instead of 2. Think of it as a rectangle and you have just added 2 lines of that rectangle instead of all the lines.

Also, it would be easier to divide the 1000m by what you get after adding the 4 sides as you would not have to guess what times into it to get just over 1000.
2. (Original post by monkeyman0121)
It looks ok but the last question I think is wrong since you just added one side of each length instead of 2. Think of it as a rectangle and you have just added 2 lines of that rectangle instead of all the lines.

Also, it would be easier to divide the 1000m by what you get after adding the 4 sides as you would not have to guess what times into it to get just over 1000.
Ok so it would be 64m.

How is dividing easier? Even if you use this method 64|1000 that is still going to take a while isn't it?
3. If you have a calculator it would be way easier but if this is a non-calc paper then do the multiplication.
4. Calculation in 2 is wrong - answers in 3 are also incorrect.
5. (Original post by Muttley79)
Calculation in 2 is wrong - answers in 3 are also incorrect.
How are they wrong?
6. 2) 154 x 40 is over 6000

3) It asks for the error not the value and upper bound is wrong
7. (Original post by Muttley79)
2) 154 x 40 is over 6000

3) It asks for the error not the value and upper bound is wrong
6160 ok I see where I made my mistake it was with 50 x 40.

Right so how do you answer error?
8. (Original post by Muttley79)
2) 154 x 40 is over 6000

3) It asks for the error not the value and upper bound is wrong
Actually hang on where does it say error?
9. For some reason quote isn;t working for me at the moment.

Error is the difference ibetween 510 and what is could be - this is 5. Upper bound is 515
10. (Original post by anon6789)
6160 ok I see where I made my mistake it was with 50 x 40.

Right so how do you answer error?
It means the greatest possible error away from the actual measurement. So the lower bound is 505kg and the upper bound is 515kg. The horse could weigh 505kg so the maximum error would be 10 kg I think.
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11. (Original post by Y11_Maths)
It means the greatest possible error away from the actual measurement. So the lower bound is 505kg and the upper bound is 515kg. The horse could weigh 505kg so the maximum error would be 10 kg I think.
But if I say 515kg then that would mean it would actually be for 520kg not 510kg since 515kg would round up to 520kg if given to the nearest 10kg.
12. (Original post by anon6789)
But if I say 515kg then that would mean it would actually be for 520kg not 510kg since 515kg would round up to 520kg if given to the nearest 10kg.
No that’s not how bounds work unfortunately.
They are usually written as:
p<_ x <q where p is the lower bound and q is the upper bound (excuse the keyboard symbols). So the upper bound is 515kg
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13. (Original post by Y11_Maths)
No that’s not how bounds work unfortunately.
They are usually written as:
p<_ x <q where p is the lower bound and q is the upper bound (excuse the keyboard symbols). So the upper bound is 515kg
Oh I see so it is the limit but isn't what is included.

So only 5.15 and 5.24 is the actual values but the limiters are 5.14 and 5.25
14. (Original post by anon6789)
Oh I see so it is the limit but isn't what is included.

So only 5.15 and 5.24 is the actual values but the limiters are 5.14 and 5.25
No it’s 505kg as the lower bound and 515kg as the upper bound giving the maximum error as 10kg. I’m not 100% sure though but I think I’m right
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15. (Original post by Y11_Maths)
No it’s 505kg as the lower bound and 515kg as the upper bound giving the maximum error as 10kg. I’m not 100% sure though but I think I’m right
Right ok just stick to 5's, got it.
16. The max error is 5 not 10
17. (Original post by Muttley79)
The max error is 5 not 10
Why is it?
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18. Rob's estimation is 510kg. The most he could be wrong by is 5kg, hence the maxium error is 5kg. It is not asking for the range of possible weights.
19. In using estimation, it would be far easier to estimate the cost as £600 and the students as 150; charging £614 for 154 students is very close to charging £600 for 150 students, which is £4 per student by the very easy calculation of 600/150. This is very very far off the charge of £40 each he's imposing, so the answer is reached through a much easier calculation.

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