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    For example, if you increased the load of what's hanging down(B), it will bring the other particle(A) closer to the pulley. However, if the hanging particle fell to the ground and the string became slack meaning A has no tension force acting on it, and A was also subject to friction, would it mean A decelerates and actually moves further away from the pulley?
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    It would mean that after B hits the floor, and the tension becomes zero, object A would still have some velocity left just with no tension pulling it. So, if friction is involved then A will keep moving towards the pulley for however far and then the friction would cause it to decelerate and come to rest.
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    (Original post by killerjayko)
    It would mean that after B hits the floor, and the tension becomes zero, object A would still have some velocity left just with no tension pulling it. So, if friction is involved then A will keep moving towards the pulley for however far and then the friction would cause it to decelerate and come to rest.
    By decelerate do you mean it goes backwards and further away from the pulley than original or moving closer to the pulley but at a slower rate?
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    Decelerate does not always mean that it moves backwards. In this case it just means that it slows down until it stops. In most cases deceleration will just mean it slows down rather than going backwards.
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    (Original post by killerjayko)
    Decelerate does not always mean that it moves backwards. In this case it just means that it slows down until it stops. In most cases deceleration will just mean it slows down rather than going backwards.
    Interesting. Thank you.
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    (Original post by dont know it)
    Interesting. Thank you.
    If the object is on a sloped table then its possible that the object could move back downwards, but in that case you could consider it to be accelerating with the positive direction being downwards
 
 
 
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