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    For part2: the method to solve it would be 6! x 7P4.
    But I don't understand how you get 7P4??
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    What is 7P4?
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    7!/(7-4)!
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    (Original post by zattyzatzat)

    For part2: the method to solve it would be 6! x 7P4.
    But I don't understand how you get 7P4??
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    (Original post by Y11_Maths)
    What is 7P4?
    The P is permutation and you'll see a button on your calculator for it.

    ^7P_4 is the total number of ways you can choose 4 objects from a set of 7 if order matters i.e. ABCD is different to ACBD.

    At GCSE you would do 7 x 6 x 5 x 4 which gives you 820 so ^7P_4 = 820
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    (Original post by Notnek)
    The P is permutation and you'll see a button on your calculator for it.

    ^7P_4 is the total number of ways you can choose 4 objects from a set of 7 if order matters i.e. ABCD is different to ACBD.

    At GCSE you would do 7 x 6 x 5 x 4 which gives you 820 so ^7P_4 = 820
    Is this GCSE work or A level?
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    (Original post by Y11_Maths)
    Is this GCSE work or A level?
    Knowing the permutations symbol is A Level but for GCSE you might be asked a question like

    How many four letter words can be made from the letters STUDENT where each letter is different.

    There are 7 choices for the first letter, 6 for the second etc. so the answer would be 7 x 6 x 5 x 4 = 840.
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    (Original post by Notnek)
    Knowing the permutations symbol is A Level but for GCSE you might be asked a question like

    How many four letter words can be made from the letters STUDENT.

    There are 7 choices for the first letter, 6 for the second etc. so the answer would be 7 x 6 x 5 x 4 = 840.
    Yeah I understand this thanks
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