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    (3f)/2 = 15cm² Solve for length f.
    Then fg = 120cm² Solve for length g.
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    (Original post by Y11_Maths)
    (3f)/2 = 15cm² Solve for length f.
    Then fg = 120cm² Solve for length g.
    I still cant get the answer im completely stuck
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    (3f)/2 = 15. Multiply both sides by 2 to get 3f = 30
    Now solve for f.

    Now you have fg = 120 so divide 120 by your value for f so you can obtain length g
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    Triangle ADE must have an area of 15cm2 as it is 135 - 120.
    Length AD must be 10, as it must multiply by half of 3 to equal 15.
    Thus, f = 10.
    g = 120/10 = 12
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    (Original post by Harry-Pikesley)
    Triangle ADE must have an area of 15cm2 as it is 135 - 120.
    Length AD must be 10, as it must multiply by half of 3 to equal 15.
    Thus, f = 10.
    g = 120/10 = 12
    Thanks
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    (Original post by Harry-Pikesley)
    Triangle ADE must have an area of 15cm2 as it is 135 - 120.
    Length AD must be 10, as it must multiply by half of 3 to equal 15.
    Thus, f = 10.
    g = 120/10 = 12
    Please dont post complete solutions on the maths forum
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