Maths Watch

lara36
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Y12_FurtherMaths
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(3f)/2 = 15cm² Solve for length f.
Then fg = 120cm² Solve for length g.
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lara36
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lara36
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(Original post by Y11_Maths)
(3f)/2 = 15cm² Solve for length f.
Then fg = 120cm² Solve for length g.
I still cant get the answer im completely stuck
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Y12_FurtherMaths
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(3f)/2 = 15. Multiply both sides by 2 to get 3f = 30
Now solve for f.

Now you have fg = 120 so divide 120 by your value for f so you can obtain length g
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Harry-Pikesley
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Triangle ADE must have an area of 15cm2 as it is 135 - 120.
Length AD must be 10, as it must multiply by half of 3 to equal 15.
Thus, f = 10.
g = 120/10 = 12
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lara36
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(Original post by Harry-Pikesley)
Triangle ADE must have an area of 15cm2 as it is 135 - 120.
Length AD must be 10, as it must multiply by half of 3 to equal 15.
Thus, f = 10.
g = 120/10 = 12
Thanks
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Y12_FurtherMaths
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(Original post by Harry-Pikesley)
Triangle ADE must have an area of 15cm2 as it is 135 - 120.
Length AD must be 10, as it must multiply by half of 3 to equal 15.
Thus, f = 10.
g = 120/10 = 12
Please dont post complete solutions on the maths forum
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lara36
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