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# Chemistry Unit 1 Hydrogen Gas Calculation watch

1. I'm going through a past paper I sat last summer & I can't find the mark scheme so I was wondering if anyone could help me with this question because I don't know if my answer is correct

On adding a strip of Mg to HCl acid, 125cm^3 of hydrogen gas formed at temp 24 degrees Celsius and a pressure of 1.01x10^5 Pa. Calculate the volume occupied by this has under the same pressure and at a temp of 52 degrees Celsius.
2. pV = nRT

You can rearrange the ideal gas law into:
p/(nR) = T/V
Since the amount of hydrogen (n), the pressure (p) and, obviously, R remain constant, p/(nR) is the same at both temperatures.

Therefore:
T1/V1 = T2/V2 (which you might have called Charles' law)

Final volume = 270 cm3 (2 d.p.)
3. (Original post by zoae)
pV = nRT

You can rearrange the ideal gas law into:
p/(nR) = T/V
Since the amount of hydrogen (n), the pressure (p) and, obviously, R remain constant, p/(nR) is the same at both temperatures.

Therefore:
T1/V1 = T2/V2 (which you might have called Charles' law)

Final volume = 270 cm3 (2 d.p.)
Thank you!!

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