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    im trying to find the reverse chain rule of 4 - (1+2x)^6

    i integrated 4 and i got 4x

    but the - sign is confusing me is it multiplying (1+2x)^6 by -1 or ....
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    (Original post by man111111)
    im trying to find the reverse chain rule of 4 - (1+2x)^6

    i integrated 4 and i got 4x

    but the - sign is confusing me is it multiplying (1+2x)^6 by -1 or ....
    So just ignore the minus sign since it's completely outside of your expression to the integrated.

    Just integrate (1+2x)^6 first then add a minus in front after it.

    4-x is the same as 4+(-1)x
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    (Original post by RDKGames)
    So just ignore the minus sign since it's completely outside of your expression to the integrated.

    Just integrate (1+2x)^6 first then add a minus in front after it.

    4-x is the same as 4+(-1)x
    so can i write my answer as 4x + (-1/14(1+2x)^7)
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    (Original post by man111111)
    so can i write my answer as 4x + (-1/14(1+2x)^7)
    Yes, though it's a bit pointless so may as well just say 4x-\frac{1}{14}(1+2x)^7
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    (Original post by RDKGames)
    Yes, though it's a bit pointless so may as well just say 4x-\frac{1}{14}(1+2x)^7
    ok thanks for your help
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    (Original post by RDKGames)
    Yes, though it's a bit pointless so may as well just say 4x-\frac{1}{14}(1+2x)^7
    can i write ∫ 4 - (1+2x)^6 as ∫ 4 - ∫ (1+2x)^6
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    (Original post by man111111)
    can i write ∫ 4 - (1+2x)^6 as ∫ 4 - ∫ (1+2x)^6
    Yes. This property should be known from C1.
 
 
 
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