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    need help in part b and d (i have no idea how to start working)

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    In this question, i need help in last part
    they have given domain so I thought that to get the range I just have to put 0 and 5 in the g(x)
    and I got a range of g(x) any value less than or equal to 0 and 10 but the correst answer is
    any value less than or equal to -2.25 and 10
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    The funny thing is I got an A* in mathematics 6 months ago but I can't even remember how to do this
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    for 7 d

    g(x) is a parabola which will have a lowest point. suppose this has y coordinate -7 then the range of the function would be y ≥ -7

    so you need to find the lowest point/ vertex/ turning point
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    (Original post by Qer)

    need help in part b and d (i have no idea how to start working)
    Consider the fact that the vertical length components of a box must add up to 4. I.e. the red + blue = 4

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    In this question, i need help in last part
    they have given domain so I thought that to get the range I just have to put 0 and 5 in the g(x)
    and I got a range of g(x) any value less than or equal to 0 and 10 but the correst answer is
    any value less than or equal to -2.25 and 10
    It's a +ve quadratic. Clearly, it has a minimum point at x=\frac{3}{2}. What is the function's value at this point? Hence since it's the MINIMUM value, the range is...?
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    still not understand ....there is 2 triangle
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    (Original post by Qer)

    still not understand ....there is 2 triangle
    Yes there is... and that's not the diagram I drew but if you want to work with yours - fine.

    The length of the red line should be obvious in terms of \theta.
    Then you want to find the vertical blue line's length in terms of \theta.

    Convince yourself that the black angle's I've marked are actually \theta, then proceed from there.

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    Took me a while but there u go use what ur given
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    (Original post by timif2)
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    Took me a while but there u go use what ur given
    thanks a lot, It also took me a while to understand what is going on by your working

    just one question we know the position of theta in one triangle how you know where is theta in 2nd question or you just use the fact they mentioned that in question
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    (Original post by Qer)
    thanks a lot, It also took me a while to understand what is going on by your working

    just one question we know the position of theta in one triangle how you know where is theta in 2nd question or you just use the fact they mentioned that in question
    For the first part, l1 and l2 are parallel, so the angle is an alternate angle, and equal

    Or you can use alternate segment theorem, which is slightly more complex, but still works

    For the second part, I just used the diagram

    For question like these I just always try to use the information I’m given and I know, then break them down to see what we’re trying to find. Good luck
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