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# Acids and bases question watch

1. can someone please explain how to work this out (the answer is B)

thanks xx
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2. pH is defined as -log[H+].

You know the initial concentration of [H+] since the acid is strong and monoprotic (one proton given out by each acid molecule).
pHinitial = -log(1) = 0

No matter how much water you add, the amount of H+ doesn't vary
ninitial = nfinal therefore (cinitial)(Vinitial) = (cfinal)(Vfinal)
cfinal = 0.01 mol dm-3 therefore pHfinal = 2

ΔpH = 2
3. (Original post by zoae)
pH is defined as -log[H+].

You know the initial concentration of [H+] since the acid is strong and monoprotic (one proton given out by each acid molecule).
pHinitial = -log(1) = 0

No matter how much water you add, the amount of H+ doesn't vary
ninitial = nfinal therefore (cinitial)(Vinitial) = (cfinal)(Vfinal)
cfinal = 0.01 mol dm-3 therefore pHfinal = 2

ΔpH = 2
I see, thank you!!

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