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    Sorry the TSR website glitched out the title is supposed to say "I-V Diode Circuit Question"
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    My answer:
    Attachment 728350728352
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    Attachment 728350728352728300

    What I don't get is why they're so wildly different, what is the curly arrow mean? Why does their circuit have a resistor on it?
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    They've drawn that to indicate a variable voltage supply - the 'curly arrow' and resisltor are being used as a potential divider.

    To make your circuit complete, you also need to add something to show you are varying the voltage supplied - either the double cell symbol with the arrow through it, or alternatively add a variable resistor in the main part of the circuit (ie beside the cell).

    If you can't vary the voltage, you can't produce a graph.
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    (Original post by Retsek)
    Sorry the TSR website glitched out the title is supposed to say "I-V Diode Circuit Question"
    Name:  Capture.PNG
Views: 14
Size:  23.6 KB
    My answer:
    Attachment 728350728352
    The mark scheme:
    Attachment 728350728352728300

    What I don't get is why they're so wildly different, what is the curly arrow mean? Why does their circuit have a resistor on it?
    I would add some “details” of what phys981 had replied.

    The whole setup is also known as a potentiometer.

    https://www.youtube.com/watch?v=uc21wl7NosY

    The “curly arrow” represents the movable jockey.

    I would not encourage that you use a variable resistor that is connected in series to the power supply and diode. There is a subtle point to this setup because it does not always produce the required I-V graph of a diode -the setup does not give the full range of the required voltages. (A question that I would set to ask students to test their understanding.)

    The setup given in the MS would definitely give the full range of the required voltages.
 
 
 
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