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    need help the markscheme doesnt help

    The curve C has parametric equations

    x=1/(t+1)
    y=1/(1-t)

    show that C satisfies the cartesian equation y = x/(2x-1)
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    you may need to edit the thread title
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    Rearrange the first equation to find a value of t in terms of x and then plug that in to the t in the y equation.
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    Rearrange the equation with x to make t the subject then sub it into the second equation.
    Love the thread title lol
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    (Original post by HateOCR)
    Rearrange the equation with x to make t the subject then sub it into the second equation.
    Love the thread title lol
    a did mate, here let me show you

    x=1/(1+t)
    t=(1/x) -1

    sub t into y

    y= 1/(1-1/x)

    which i get as -x/1 = -x
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    I got
    (Original post by awijdijwajiodji)
    a did mate, here let me show you

    x=1/(1 t)
    t=(1/x) -1

    sub t into y

    y= 1/(1-1/x)

    which i get as -x/1 = -x
    I got y=1/(2-1/x)
    You can factorise 2x-1 so you get
    Y=1/1/x(2x-1)
    1/1/x is the same as x so
    Y=x/(2x-1)

    You didnt sub it back in correctly
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    Here sorry for the scrunched up paper i threw it after i solved it lol
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    (Original post by HateOCR)
    Here sorry for the scrunched up paper i threw it after i solved it lol
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    on the 6th line idk why you took out 2x-1 how do you know how to do that?
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    (Original post by awijdijwajiodji)
    on the 6th line idk why you took out 2x-1 how do you know how to do that?
    Because the question says it was 2x-1 in the denominator. Also if you try expanding the bracket you will see you end up with 2-1/x therefore it works.
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