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    is it me or has the tutor got this example horribly wrong?

    for the second row: he said that you have to make the column 0 - this was achieved by taking away 5. he said you do the same to every cell in this Row and you multiply it by the value in the cell above, from the new (second) table.

    so, in his own words for cell (row: s, column: x2): (6-5)x(3/4)

    for me, this equaled 3/4, but for him its 2 1/4.

    whats going on?!!
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    No he has done it right. The operation you are performing to the second row is R2-5R1. So (6) - (5x3/4) = 9/4. Remember you are using the new values of row 1.
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    (Original post by k92e67)
    No he has done it right. The operation you are performing to the second row is R2-5R1. So (6) - (5x3/4) = 9/4. Remember you are using the new values of row 1.
    what are you getting for row: X1, column: r???

    so, the method is: 9/67 - (48/67 x 24/73) ???
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    (Original post by k92e67)
    No he has done it right. The operation you are performing to the second row is R2-5R1. So (6) - (5x3/4) = 9/4. Remember you are using the new values of row 1.
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    (Original post by Maths&physics)
    what are you getting for row: X1, column: r???

    so, the method is: 9/67 - (48/67 x 24/73) ???
    Yes that’s it

    You want to make the cell in row x1 column x2 zero. So to do that we want to use the operation: R1-(48/67)R3 as this will make the value 0 in the x2 column. So we do this to all cells in the x1 row.

    The R3 values we’re using are the new ones as shown in the second table
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    (Original post by k92e67)
    Yes that’s it

    You want to make the cell in row x1 column x2 zero. So to do that we want to use the operation: R1-(48/67)R3 as this will make the value 0 in the x2 column. So we do this to all cells in the x1 row.

    The R3 values we’re using are the new ones as shown in the second table
    so, the values I was using were right but the're giving me a different value for row: X1, column: r.

    he has got: 27/73

    I got: 9/67 -[( 48/67)(24/73)] = -495/4891
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    (Original post by Maths&physics)
    so, the values I was using were right but the're giving me a different value for row: X1, column: r.

    he has got: 27/73

    I got: 9/67 -[( 48/67)(24/73)] = -495/4891
    strange, im getting that too. unless he's done something wrong, im not sure why that is. maybe somebody else can have a look
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    (Original post by k92e67)
    strange, im getting that too. unless he's done something wrong, im not sure why that is. maybe somebody else can have a look
    did you study D2?

    thanks, but it seems no one else is replying.
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    (Original post by Maths&physics)
    did you study D2?
    sitting the exam this year, im just doing papers for it currently
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    (Original post by k92e67)
    sitting the exam this year, im just doing papers for it currently
    which otherexams are you doing? when did you start the papers?
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    (Original post by Maths&physics)
    which otherexams are you doing? when did you start the papers?
    fp1-3 m1-5 s1-4

    a little over a month ago
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    (Original post by k92e67)
    fp1-3 m1-5 s1-4

    a little over a month ago
    have you finished learning everything already?
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