stuck on how to approach this maths question Watch

Gent2324
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solve the following:
-2<x-3<5
1<x+1<9

Solve the following pairs of inequalities, find the integer value which satisfies both of them.
x-3>2 and 2x+1<15
1-2x<17 and (2-3x)/10 > 2
how do i do these types of questions im not to sure thanks
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B_9710
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(Original post by Gent2324)
solve the following:
-2<x-3<5
1<x+1<9

Solve the following pairs of inequalities, find the integer value which satisfies both of them.
x-3>2 and 2x+1<15
1-2x<17 and (2-3x)/10 > 2
how do i do these types of questions im not to sure thanks
Can you solve inequalities on their own, so can you solve x-3>2 ?
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Gent2324
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(Original post by B_9710)
Can you solve inequalities on their own, so can you solve x-3>2 ?
yes x>5
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Y12_FurtherMaths
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Whatever you do to one side of the inequality you must do to both. So for your first example: −2<α−3<5 add 3 to both sides do you get 1<α<8 where α is x
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B_9710
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(Original post by Gent2324)
yes x>5
So solve each of the inequalities separately and then you can put them together.
For instance if I solve two inequalities and I get -1<x<6 and -2<x<5 combining these I'd get -1<x<5 and x must satisfy both inequalities.
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Gent2324
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(Original post by Y11_Maths)
Whatever you do to one side of the inequality you must do to both. So for your first example: −2<α−3<5 add 3 to both sides do you get 1<α<8 where α is x
ah ok i think i get it now, do you mean to add 3 on all 3 sides?

(Original post by B_9710)
So solve each of the inequalities separately and then you can put them together.
For instance if I solve two inequalities and I get -1<x<6 and -2<x<5 combining these I'd get -1<x<5 and x must satisfy both inequalities.
ah alright so for
1-2x<17 and (2-3x)/10 > 2

1<17+2x so -16<2x
-8<x

(2-3x)/10 > 2
2-3x > 20
2>20+3x
-18>3x
-6>x
so the is the final inequality -8<x<-6
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Y12_FurtherMaths
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(Original post by Gent2324)
ah alright so for
1-2x<17 and (2-3x)/10 > 2

1<17+2x so -16<2x
-8<x

(2-3x)/10 > 2
2-3x > 20
2>20+3x
-18>3x
-6>x
so the is the final inequality -8<x<-6
Yes
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