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# Maths question help watch

1. 1. 3 easter bunnies, Flopsy, Mopsy and Popsy, share a bag of carrots. Mopsy and Popsy eat 8/15 of the carrots. Flopsy and Mopsy eat 11/12 of the carrots. If each of them eat a whole number of carrots, what is the smallest possible number of carrots in the bag?

2. If you divide a tube of mini eggs into 2 unequal piles, then 30 times the difference between the 2 piles equal the difference between the squares of the 2 piles. How many mini eggs are in the tube?
2. (Original post by Sxv_)
1. 3 easter bunnies, Flopsy, Mopsy and Popsy, share a bag of carrots. Mopsy and Popsy eat 8/15 of the carrots. Flopsy and Mopsy eat 11/12 of the carrots. If each of them eat a whole number of carrots, what is the smallest possible number of carrots in the bag?

2. If you divide a tube of mini eggs into 2 unequal piles, then 30 times the difference between the 2 piles equal the difference between the squares of the 2 piles. How many mini eggs are in the tube?
What have you tried?
3. (Original post by Muttley79)
What have you tried?
I'm not getting anywhere
4. (Original post by Sxv_)
I'm not getting anywhere
I think the second one is easier - I'd start with that.

Call the number in one pile 'a' and the other pile 'b'. Can you make some equations?
5. (Original post by Muttley79)
I think the second one is easier - I'd start with that.

Call the number in one pile 'a' and the other pile 'b'. Can you make some equations?
it would be nice if you could provide a solution that I could learn from
6. (Original post by Muttley79)
I think the second one is easier - I'd start with that.

Call the number in one pile 'a' and the other pile 'b'. Can you make some equations?
I think I got a solution for the first one are you able to check it for me
7. well you can say that the number of carrots, C , must be a multiple of 15 and also 12....
8. (Original post by Sxv_)
I think I got a solution for the first one are you able to check it for me
Yes - I've done both of them.
9. For question 1,

M + P = 8/15
F + P = 11/12
Therefore, M + F + 2P = 29/20
Since you know that M + F + P =1, P=9/20
M= 8/15 - 9/20 = 1/12
F= 11/12 - 920 = 7/15
What is the LCM of 12,15 and 20, it's 60.

For question 2)

Let the sum of the mini eggs be "x" and the piles be "a" and "b"
x = a + b
30(a - b) = a^2 - b^2
30(a - b) = (a + b)(a - b)
30 = a + b
30 = x
So there are 30 mini eggs
For question 1,

M + P = 8/15
F + P = 11/12
Therefore, M + F + 2P = 29/20
Since you know that M + F + P =1, P=9/20
M= 8/15 - 9/20 = 1/12
F= 11/12 - 920 = 7/15
What is the LCM of 12,15 and 20, it's 60.

For question 2)

Let the sum of the mini eggs be "x" and the piles be "a" and "b"
x = a + b
30(a - b) = a^2 - b^2
30(a - b) = (a + b)(a - b)
30 = a + b
30 = x
So there are 30 mini eggs
Yes I agree - my method was a bit quicker but this is fine.

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