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    Write a half equation for the formation of oxygen at the anode in the electrolysis of water diluted with sulfuric acid
    Pls explain and help!! Thanksss
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    (Original post by Berrydo)
    Write a half equation for the formation of oxygen at the anode in the electrolysis of water diluted with sulfuric acid
    Pls explain and help!! Thanksss
    Anyone able to answer and explain that, would probably get a Nobel prize!

    Firstly, you mean to say sulfuric acid diluted with water?

    Then, in the electrolysis of aqueous sulfuric acid, hydrogen gas is formed at the anode, whilst oxygen gas is formed at the cathode.

    Trick question? Or typo's?
 
 
 
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