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Confused:Rate Of Hydrolysis of primary Haloalkanes watch

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    Im doing A level OCR chemistry and we did a practical on 'rate of hydrolysis of primary Haloalkanes'.

    The method sheet we were given wasn't clear hence I was wondering if someone could outline the method in detail. We used chlorobutane,bromobutane and iodobutane in conjunction with ethanol and silver nitrate.

    I was also wondering whats the purpose of the ethanol and silver nitrate.
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    You would use the ethanol to completley dissolve everything in the mixture and the silver nitrate is used to produce the precipitate so you know which
    halogen has been hydrolysed in which order.

    So because the C-I bond is the weakest you should get the yellow silver iodide precipitate being formed first becuase it is hydrolysed before the C-Br and
    C-Cl bond because it is the weakest (and iodine is the least reactive halogen so it forms weaker bonds compared to bromine and chlorine).
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    (Original post by SpicyMemes69)
    You would use the ethanol to completley dissolve everything in the mixture and the silver nitrate is used to produce the precipitate so you know which
    halogen has been hydrolysed in which order.

    So because the C-I bond is the weakest you should get the yellow silver iodide precipitate being formed first becuase it is hydrolysed before the C-Br and
    C-Cl bond because it is the weakest (and iodine is the least reactive halogen so it forms weaker bonds compared to bromine and chlorine).
    Thanks a lot for brief explanation!
 
 
 
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