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    Hi all,
    I got this question as part of a worksheet for mechanics, but the lecture was cancelled, and the only materials provided to help werent very useful. Any guidance on how to go about solving (ii)?

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    As always, thanks a ton in advance
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    (Original post by thomoski2)
    Hi all,
    I got this question as part of a worksheet for mechanics, but the lecture was cancelled, and the only materials provided to help werent very useful. Any guidance on how to go about solving (ii)?

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    As always, thanks a ton in advance
    The component of a in the direction of b is |a|\cos \theta where \theta is the angle between a and b. This is just trig. But by definition a\cdot b=|a||b|\cos \theta, from which the component of a in the direction of b is given by \dfrac{a\cdot b}{|b|}
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    (Original post by old_engineer)
    The component of a in the direction of b is |a|\cos \theta where \theta is the angle between a and b. This is just trig. But by definition a\cdot b=|a||b|\cos \theta, from which the component of a in the direction of b is given by \dfrac{a\cdot b}{|b|}
    Could you put that in an example?
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    (Original post by thomoski2)
    Could you put that in an example?
    In part (i) of the question you have already found |b| and have been told that a\cdot b=4. The component of a in the direction of b is the second of these divided by the first.
 
 
 
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