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# core 3 - integration by parts watch

1. Use integration by parts to integrate : xsec^2 dx. (4 marks)
= xtanx -ln(secx) + c
Hence integrate xtan^2x dx : (3 marks)

Working out :
u=x
du/dx=1

dv/dx = tan^2x
V =

How do i integrate tan^2x??
2. How are sec^2 and tan^2 linked?
3. tan^2x=sec^2x-1

Now differentiate
4. I.e. Can we like tan^2 and sec^2 with an identity?
5. If tan^2x = sec^2x -1 ,
is this ^^ being substituted in for tan^2x to get :
integrate x (sec^2x -1) dx?
6. (Original post by Chelsea12345)
If tan^2x = sec^2x -1 ,
is this ^^ being substituted in for tan^2x to get :
integrate x (sec^2x -1) dx?
yup- as you already know the integral of xsec^2x
7. (Original post by psc---maths)
yup- as you already know the integral of xsec^2x
thankyou!

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