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# Help with Route Inspection watch

1. Hi. So for part (b), I tried to add up all the expressions and set it equal to 100, then collect all the x terms together to find out the value of x. But I get 19/2 x = 126, which isn't right. Please could some help me?

2. (Original post by ℓove)
Hi. So for part (b), I tried to add up all the expressions and set it equal to 100, then collect all the x terms together to find out the value of x. But I get 19/2 x = 126, which isn't right. Please could some help me?

The graph is not Eulerian. You have to cover one of the arcs twice.
3. (Original post by ghostwalker)
The graph is not Eulerian. You have to cover one of the arcs twice.
Would it be BC because both B and C have an odd number of vertices?
4. (Original post by ℓove)
Would it be BC because both B and C have an odd number of vertices?
Yes.

That is the obvious one to go for.

Note: The shortest route from B to C, is not necessarily the direct one.

It could be BA + BC, or BD + DE + EC.

If you work out the value of x for each of those possibilities, then in each case you will find BC is shorter than the chosen extra route, so you wouldn't choose that latter route.

Hence BC is the one you want.
5. (Original post by ghostwalker)
Yes.

That is the obvious one to go for.

Note: The shortest route from B to C, is not necessarily the direct one.

It could be BA + BC, or BD + DE + EC.

If you work out the value of x for each of those possibilities, then in each case you will find BC is shorter than the chosen extra route, so you wouldn't choose that latter route.

Hence BC is the one you want.
Thank youu!

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