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    How do you find the time distance travelled in a displacement-time graph?

    If a boy throws a tennis ball vertically upwards at a inital velocity of 22ms-1
    State the velocity of the ball when it is a maximum height
    Total time of flight of the ball if caught at the same height from which it was thrown?

    I am jumping and my highess point is 5m above the ground
    How do I find the velocity at which I leave the surface of the ground?
    How long will it take me to reach the height?
    My velocity when I land on the ground?

    Thank you in advance
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    (Original post by lockwood6)
    How do you find the time distance travelled in a displacement-time graph?

    If a boy throws a tennis ball vertically upwards at a inital velocity of 22ms-1
    State the velocity of the ball when it is a maximum height
    Total time of flight of the ball if caught at the same height from which it was thrown?

    I am jumping and my highess point is 5m above the ground
    How do I find the velocity at which I leave the surface of the ground?
    How long will it take me to reach the height?
    My velocity when I land on the ground?

    Thank you in advance
    Have you learned the SUVAT equations?

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    (Original post by lockwood6)
    How do you find the time distance travelled in a displacement-time graph?
    Distance is the absolute value of displacement. So turn all the displacement parts into positive numbers and add them up all together.

    (Original post by lockwood6)
    If a boy throws a tennis ball vertically upwards at a inital velocity of 22ms-1
    State the velocity of the ball when it is a maximum height
    Total time of flight of the ball if caught at the same height from which it was thrown?
    1)Always start off like this:

    Horizontal
    ------
    s=
    u=
    v=
    a=
    t=

    Vertical
    ---------
    s=
    u=
    v=
    a=
    t=


    2)Fill in the gaps with the given information. If no assumptions given, you can make your own.

    I usually assume that the object is a particle in these questions. So you ignore the air resistance acting on the particle.



    Horizontal
    ------
    s=
    u=
    v=
    a=0
    t=

    Vertical
    ---------
    s=
    u=22m/s
    v=0
    a=-9.81 m/s
    t=

    The velocity of the ball at it's maximum height should be 0, if it helps draw a sketch of the ball. It has the shape of a parabola, so the velocity at the maximum point=0.

    3)
    Rearrange one of the suvat equations:




    I choose [1].

    So I rearrange [1] with respect to t; t = (v-u)/a
    =(0-22)/-9.81 = 2.242609582...s

    =2.2s
 
 
 
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