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# Physics watch

1. How do you find the time distance travelled in a displacement-time graph?

If a boy throws a tennis ball vertically upwards at a inital velocity of 22ms-1
State the velocity of the ball when it is a maximum height
Total time of flight of the ball if caught at the same height from which it was thrown?

I am jumping and my highess point is 5m above the ground
How do I find the velocity at which I leave the surface of the ground?
How long will it take me to reach the height?
My velocity when I land on the ground?

2. (Original post by lockwood6)
How do you find the time distance travelled in a displacement-time graph?

If a boy throws a tennis ball vertically upwards at a inital velocity of 22ms-1
State the velocity of the ball when it is a maximum height
Total time of flight of the ball if caught at the same height from which it was thrown?

I am jumping and my highess point is 5m above the ground
How do I find the velocity at which I leave the surface of the ground?
How long will it take me to reach the height?
My velocity when I land on the ground?

Have you learned the SUVAT equations?

3. (Original post by lockwood6)
How do you find the time distance travelled in a displacement-time graph?
Distance is the absolute value of displacement. So turn all the displacement parts into positive numbers and add them up all together.

(Original post by lockwood6)
If a boy throws a tennis ball vertically upwards at a inital velocity of 22ms-1
State the velocity of the ball when it is a maximum height
Total time of flight of the ball if caught at the same height from which it was thrown?
1)Always start off like this:

Horizontal
------
s=
u=
v=
a=
t=

Vertical
---------
s=
u=
v=
a=
t=

2)Fill in the gaps with the given information. If no assumptions given, you can make your own.

I usually assume that the object is a particle in these questions. So you ignore the air resistance acting on the particle.

Horizontal
------
s=
u=
v=
a=0
t=

Vertical
---------
s=
u=22m/s
v=0
a=-9.81 m/s
t=

The velocity of the ball at it's maximum height should be 0, if it helps draw a sketch of the ball. It has the shape of a parabola, so the velocity at the maximum point=0.

3)
Rearrange one of the suvat equations:

I choose [1].

So I rearrange [1] with respect to t; t = (v-u)/a
=(0-22)/-9.81 = 2.242609582...s

=2.2s

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Updated: March 6, 2018
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