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    https://gyazo.com/135d140bd0b6380ccea5a2cf4c6214c5

    Help with part one of question please
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    (Original post by Jian17)
    https://gyazo.com/135d140bd0b6380ccea5a2cf4c6214c5

    Help with part one of question please
    You are told a = - 2222 and d = 17

    What's the formula for the nth term of an AP?

    Once you have that then make an equation as we want nth term > 0
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    Same thing ine just a bit neater/ nicer

    if you know that -2222 if term one and difference is 17 i.e. next term is -2205 etc. You know 100 terms on is +1700 basically fudge the way by doing -2222/17 to work out how many 17s add to get close to 0 .

    2) Formula : nth term =a + d(n-1)
    U need when goes over 0
    So solve by 0>a+d(n-1)
    0> -2222+17(n-1)
    Then that should give u no terms when is 0. Next whole
    Number of N (I assume answer will be decimal) is term which exceeds formula.
    Plug that N back into the formula or just add 17 that many times.
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    Thanks for both answers, i managed to do the question!!
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    (Original post by Canary84)
    Same thing ine just a bit neater/ nicer

    .
    MY post was following the rules to just give hints ...

    Please - not as much detail next time you help someone in the maths forum. Please read the rules
 
 
 
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