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    x=qt+2 and y=t^3 + q

    y intercept f curve is (0, 617/25)

    I have tried doing the question but im not getting the right answer , could someone start me off . Thanks
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    (Original post by HelloImCool)
    x=qt+2 and y=t^3 + q

    y intercept f curve is (0, 617/25)

    I have tried doing the question but im not getting the right answer , could someone start me off . Thanks
    Well, what is the question?
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    What exactly is the question?
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    (Original post by RDKGames)
    Well, what is the question?
    oh sorry find x and y intercept and find what q is
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    (Original post by Radioactivedecay)
    What exactly is the question?
    find x and y intercept coordinates
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    You know that at the y intercept the x value is 0, so you can use that to find t in terms of q and then use other equation to find q.
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    (Original post by HelloImCool)
    oh sorry find x and y intercept
    Well the y-intercept is right there so you don't need to do anything.

    To get the x intercept, you want to set y=0 then find the value of t. Firstly, of course, you'd like to determine what the value of q is. To do that, you need to use the fact that the curve crosses (0,\frac{617}{25}) which means that at some point t=T, we have 0=qT+2 and \dfrac{617}{25} = T^3 + q. This yields a system of two equations in two unknowns - solve it to obtain q.
 
 
 
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