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    Hi can anyone check this for me please x
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    (Original post by Mya_oty)
    Hi can anyone check this for me please x
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    Question one makes no sense. A line cannot be perpendicular to a point. Who knows what was intended? Probably the line through A, perpendicular to L.

    Part (a), you should write your answer as a column vector.

    Part (b) is correct.

    Part (c). A unit vector has magnitude = 1. To get a unit vector in a given direction, divide a vector in that direction by its magnitude.
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    (Original post by Mya_oty)
    Hi can anyone check this for me please x
    In Q1 you have found a equation for line L but that is not what the question asks for. The question asks for “the line that is perpendicular to point A”, which is meaningless but I guess the intention was “the line that is perpendicular to L at point A”.

    Q2 looks OK.
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    okay thanks, how do I work out the rest of question 1?
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    (Original post by BuryMathsTutor)
    Question one makes no sense. A line cannot be perpendicular to a point. Who knows what was intended.

    Part (a), you should write your answer as a column vector.

    Part (b) is correct.

    Part (c). A unit vector has magnitude = 1. To get a unit vector in a given direction, divide a vector in that direction by its magnitude.
    so part (c) needs to be (6,6) ÷ 6√2
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    (Original post by Mya_oty)
    so part (c) needs to be (6,6) ÷ 6√2
    Yes. :thumbsup:

    Also, simplify and write as a column vector.
 
 
 
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