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# Vectors - can someone check my answer watch

1. Hi can anyone check this for me please x
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2. (Original post by Mya_oty)
Hi can anyone check this for me please x
Question one makes no sense. A line cannot be perpendicular to a point. Who knows what was intended? Probably the line through A, perpendicular to L.

Part (a), you should write your answer as a column vector.

Part (b) is correct.

Part (c). A unit vector has magnitude = 1. To get a unit vector in a given direction, divide a vector in that direction by its magnitude.
3. (Original post by Mya_oty)
Hi can anyone check this for me please x
In Q1 you have found a equation for line L but that is not what the question asks for. The question asks for “the line that is perpendicular to point A”, which is meaningless but I guess the intention was “the line that is perpendicular to L at point A”.

Q2 looks OK.
4. okay thanks, how do I work out the rest of question 1?
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5. (Original post by BuryMathsTutor)
Question one makes no sense. A line cannot be perpendicular to a point. Who knows what was intended.

Part (a), you should write your answer as a column vector.

Part (b) is correct.

Part (c). A unit vector has magnitude = 1. To get a unit vector in a given direction, divide a vector in that direction by its magnitude.
so part (c) needs to be (6,6) ÷ 6√2
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6. (Original post by Mya_oty)
so part (c) needs to be (6,6) ÷ 6√2
Yes.

Also, simplify and write as a column vector.

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