Amount of substance question
How would u answer the following question???
The removal of silicon dioxide with limestone in the blast furnace can be represents by the following equation. CaCO3 (s) + SiO2 (s) > CaSiO3 (l) + CO2 (g)
The volume of carbon dioxide, measured at 298k and 1.01x 10^5 pa, formed in this reaction during the removal of 1.00 tonne (1000kg) of silicon dioxide is?
The removal of silicon dioxide with limestone in the blast furnace can be represents by the following equation. CaCO3 (s) + SiO2 (s) > CaSiO3 (l) + CO2 (g)
The volume of carbon dioxide, measured at 298k and 1.01x 10^5 pa, formed in this reaction during the removal of 1.00 tonne (1000kg) of silicon dioxide is?
Reply 1
Original post by imann
How would u answer the following question???
The removal of silicon dioxide with limestone in the blast furnace can be represents by the following equation. CaCO3 (s) + SiO2 (s) > CaSiO3 (l) + CO2 (g)
The volume of carbon dioxide, measured at 298k and 1.01x 10^5 pa, formed in this reaction during the removal of 1.00 tonne (1000kg) of silicon dioxide is?
The removal of silicon dioxide with limestone in the blast furnace can be represents by the following equation. CaCO3 (s) + SiO2 (s) > CaSiO3 (l) + CO2 (g)
The volume of carbon dioxide, measured at 298k and 1.01x 10^5 pa, formed in this reaction during the removal of 1.00 tonne (1000kg) of silicon dioxide is?
Correctly, I would hope.
How would YOU answer it?
Reply 3
1 tonne = 1000kg = 1,000,000g
Mass = Mr. Moles
1,000,000 / (28.1 16 16) = 16638.935... (I kept the answer stored in my calculator for accuracy)
It’s a 1:1 ratio shown in the equation then you plug it into the re arranged
Pv=nRT v=nRT/P
16636.935 x 8.31 x 298 / 1.01x10^5
=407.963625 m^3
≈408m^3 (DONT FORGET THE UNIT M^3!!!)
Mass = Mr. Moles
1,000,000 / (28.1 16 16) = 16638.935... (I kept the answer stored in my calculator for accuracy)
It’s a 1:1 ratio shown in the equation then you plug it into the re arranged
Pv=nRT v=nRT/P
16636.935 x 8.31 x 298 / 1.01x10^5
=407.963625 m^3
≈408m^3 (DONT FORGET THE UNIT M^3!!!)
(edited 4 years ago)
Original post by chiprylance
1 tonne = 1000kg = 1,000,000g
Mass = Mr. Moles
1,000,000 / (28.1 16 16) = 16638.935... (I kept the answer stored in my calculator for accuracy)
It’s a 1:1 ratio shown in the equation then you plug it into the re arranged
Pv=nRT v=nRT/P
16636.935 x 8.31 x 298 / 1.01x10^5
=407.963625 m^3
≈408m^3 (DONT FORGET THE UNIT M^3!!!)
Mass = Mr. Moles
1,000,000 / (28.1 16 16) = 16638.935... (I kept the answer stored in my calculator for accuracy)
It’s a 1:1 ratio shown in the equation then you plug it into the re arranged
Pv=nRT v=nRT/P
16636.935 x 8.31 x 298 / 1.01x10^5
=407.963625 m^3
≈408m^3 (DONT FORGET THE UNIT M^3!!!)
heyy (ik u answered this a year ago),
i have a q: isn't the SI of mass of kg? yet, that's the only way to get the answer...
Reply 5
Original post by chiprylance
1 tonne = 1000kg = 1,000,000g
Mass = Mr. Moles
1,000,000 / (28.1 16 16) = 16638.935... (I kept the answer stored in my calculator for accuracy)
It’s a 1:1 ratio shown in the equation then you plug it into the re arranged
Pv=nRT v=nRT/P
16636.935 x 8.31 x 298 / 1.01x10^5
=407.963625 m^3
≈408m^3 (DONT FORGET THE UNIT M^3!!!)
Mass = Mr. Moles
1,000,000 / (28.1 16 16) = 16638.935... (I kept the answer stored in my calculator for accuracy)
It’s a 1:1 ratio shown in the equation then you plug it into the re arranged
Pv=nRT v=nRT/P
16636.935 x 8.31 x 298 / 1.01x10^5
=407.963625 m^3
≈408m^3 (DONT FORGET THE UNIT M^3!!!)
why is it m^3 not dm^3
Reply 6
Original post by ctorres9
why is it m^3 not dm^3
It's the units the volume for it to be in the equation.
So in the pV=nRT equation:
Pressure always has to be in the units Pascals (Pa)
Temperature always has to be in the units Kelvin (K)
Volume has to always be in metres cubes
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