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    A bullet is fired by a gun which is 4kg heavier than the bullet. Immediately after the bullet is fired, it is moving with speed 200ms^-1 and the gun recoils in the opposite direction with speed 5ms^-1.

    Find the mass of the bullet
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    since there is conservation of momentum,
    the recoil velocity of gun x mass of gun = mass of bullet x speed of the bullet.
    Let the mass of the bullet be m.
    Please work out from here.
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    (Original post by SumOfSquares)
    since there is conservation of momentum,
    the recoil velocity of gun x mass of gun = mass of bullet x speed of the bullet.
    Let the mass of the bullet be m.
    Therefore,
    5x (4+m) = 200x m
    20 + 5m = 200m
    20 = 195m
    Therefore m = 20/195 kg = 0.10 kg to 2dp
    Have you perhaps seem the forum guideline (sticky at the top) about not posting full solutions?
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    (Original post by old_engineer)
    Have you perhaps seem the forum guideline (sticky at the top) about not posting full solutions?
    changed it. sorry about that.
 
 
 
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Updated: March 11, 2018
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