# drawing graph for transformed equationWatch

Announcements
#1
y=4/x-6 plus 5

What are the intercepts and assymptotes?
0
1 year ago
#2
Let f(x)=1/x. f(x-6)=1/(x-6). This transformation shifts the graph 6 units to the right.
4f(x-6)=4/(x-6). This corresponds to a vertical stretch on the previous graph of scale factor 4.
4f(x-6) 5=4/(x-6) 5. This means that we translate the previous graph 5 units upwards.

If u consider the asymptotes of f(x) and how the graph changes as a result of each transformation happening one after the other, u should be able to follow through and obtain values for the asymptotes.

Alternatively u could let x tend towards infinity, and make the denominator of the fraction equal zero.
0
#3
(Original post by Shaanv)
Let f(x)=1/x. f(x-6)=1/(x-6). This transformation shifts the graph 6 units to the right.
4f(x-6)=4/(x-6). This corresponds to a vertical stretch on the previous graph of scale factor 4.
4f(x-6)+5=4/(x-6) + 5. This means that we translate the previous graph 5 units upwards.

If u consider the asymptotes of f(x) and how the graph changes as a result of each transformation happening one after the other, u should be able to follow through and obtain values for the asymptotes.

Alternatively u could let x tend towards infinity, and let x tend towards 6 from above and below and find the values that the function approaches but never reaches.
so are the assymptotes the same as the x and y interceptions
0
1 year ago
#4
(Original post by Mark jam)
so are the assymptotes the same as the x and y interceptions
Nope, the asymptotes are what the graph approaches but never reaches.

Hold on a second im gonna try making a visual aid to help u figure out what is happening.
0
1 year ago
#5

Follow the graphs and how the asymptotes change with each individual transformation as i described above.
0
#6
Ok thanks i understand!
0
1 year ago
#7
(Original post by Shaanv)
Nope, the asymptotes are what the graph approaches but never reaches.
It can definitely reach it, ie intersects its own horizontal asymptote, so just a better choice of words is required.
0
1 year ago
#8
(Original post by RDKGames)
It can definitely reach it, ie intersects its own horizontal asymptote, so just a better choice of words is required.
Oh my bad. How would you word it?
0
1 year ago
#9
(Original post by Shaanv)
Oh my bad. How would you word it?
An asymptote is a certain line which the graph of our function approaches as it tends to plus/minus infinity
0
X

new posts
Back
to top
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### University open days

• The University of Law
The Bar Series: Applications and Interviews - London Bloomsbury campus Postgraduate
Thu, 17 Oct '19
• Cardiff Metropolitan University
Sat, 19 Oct '19
• Coventry University
Sat, 19 Oct '19

### Poll

Join the discussion

#### How has the start of this academic year been for you?

Loving it - gonna be a great year (142)
17.95%
It's just nice to be back! (213)
26.93%
Not great so far... (283)
35.78%
I want to drop out! (153)
19.34%