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    Hi guys,
    I don't quite understand the answer to this question.. they have left out the one hydrogen that causes the peak at 3.8 in H-C-C=O (hydrogen bonded to a carbon that is bonded to a carbon that is double bonded to an oxygen). Can someone please help me understand this?
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    (Original post by sienna2266)
    Hi guys,
    I don't quite understand the answer to this question.. they have left out the one hydrogen that causes the peak at 3.8 in H-C-C=O (hydrogen bonded to a carbon that is bonded to a carbon that is double bonded to an oxygen). Can someone please help me understand this?
    Name:  28.PNG
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    Attachment 730586730588
    Nothing has been left out.

    The two methyl groups to the RHS are equivalent and give rise to a 6 proton singlet
    The CH2 in the middle gives rise to a 2 proton singlet
    The OH group gives rise to a 1 proton singlet
    The CH3 to the LHS shows up as a 3 proton singlet.
    --------------------------------------------------------------------- add protons = 12
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    (Original post by charco)
    Nothing has been left out.

    The two methyl groups to the RHS are equivalent and give rise to a 6 proton singlet
    The CH2 in the middle gives rise to a 2 proton singlet
    The OH group gives rise to a 1 proton singlet
    The CH3 to the LHS shows up as a 3 proton singlet.
    --------------------------------------------------------------------- add protons = 12
    Thank you I just realised my mistake.. The peak at 3.8 can be from a hydrogen in H-C-C=O or a hydrogen in O-H or a hydrogen in N-H but since it says in the question that this compound has an O-H group, then the 1 proton singlet is caused by the hydrogen in O-H.
 
 
 
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