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I am stuck on 8 b

2. I keep getting 321° to the nearest degree by subtracting B from A and getting 4i-5j then working out the bearing from that. Tan theta= 4/5 thus the angle is 51.34+ 270= 321°. However, the answers of the back of the book state that the angle is 303°.

What have I done incorrectly?
3. (Original post by GCSE pupil)
I keep getting 321° to the nearest degree by subtracting B from A and getting 4i-5j then working out the bearing from that. Tan theta= 4/5 thus the angle is 51.34+ 270= 321°. However, the answers of the back of the book state that the angle is 303°.

What have I done incorrectly?
There's something strange in your working, as [email protected] = 4/5 leads to @ = 38.66 deg. However, this angle of 38 deg is measured anticlockwise from North, so the clockwise bearing, again from North, is 360 - 38.66 = 321 deg. So I think the bearing of A from B is indeed 321 deg, but you have arrived at that answer via a strange route!

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Updated: March 12, 2018
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