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    Okay, so I know what I'm doing when you're trying to convert to Cartesian with r=sin(vita)

    However, how do i go about it when you have r=sin2(vita)?

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    (Original post by xAikx)
    Okay, so I know what I'm doing when you're trying to convert to Cartesian with r=sin(vita)

    However, how do i go about it when you have r=sin2(vita)?

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    First use the \sin 2\theta identity

    then multiply both sides by r^2 so you have r\sin \theta and r\cos\theta on the RHS.
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    (Original post by xAikx)
    Okay, so I know what I'm doing when you're trying to convert to Cartesian with r=sin(vita)

    However, how do i go about it when you have r=sin2(vita)?
    Vita...? It’s theta.

    You dont need to convert to Cartesian. It’s straight-forward doing it from the eq here.

    It will start at 0, will increase to 3 as theta goes up to pi/4, then down to 0 as it goes to pi/2, and so on until 2pi
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    (Original post by RDKGames)
    Vita...? It’s theta.

    You dont need to convert to Cartesian. It’s straight-forward doing it from the eq here.

    It will start at 0, will increase to 3 as theta goes up to pi/4, then down to 0 as it goes to pi/2, and so on until 2pi
    Good point. I didn't read the question properly and assumed the OP needed to convert to cartesian.
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    (Original post by Notnek)
    Good point. I didn't read the question properly and assumed the OP needed to convert to cartesian.
    I feel like it’s more of a nightmare attempting to sketch from the actual Cartesian form without noticing a few things like symmetry.
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    (Original post by RDKGames)
    I feel like it’s more of a nightmare attempting to sketch from the actual Cartesian form without noticing a few things like symmetry.
    Yes sketching using the cartesian form is definitely not the way to do this question.
 
 
 
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