Percentage yield
Calculate the mass of phenylamine that was produced from the 3.69 g of
nitrobenzene in this experiment. Give your answer to three significant figures.
Mr
: nitrobenzene,123; phenylamine, 93.1
IN QUESTION: Purification gave a 72.1% yield of phenylamine.
Do we use to percentage yield equation and rearrange after calculating moles of nitrobenzene? that's all that I can think of? Is it the wrong way of thinking?
I just wanna make sure I don't over complicate things
nitrobenzene in this experiment. Give your answer to three significant figures.
Mr
: nitrobenzene,123; phenylamine, 93.1
IN QUESTION: Purification gave a 72.1% yield of phenylamine.
Do we use to percentage yield equation and rearrange after calculating moles of nitrobenzene? that's all that I can think of? Is it the wrong way of thinking?
I just wanna make sure I don't over complicate things
(edited 6 years ago)
Original post by chemquestion
Calculate the mass of phenylamine that was produced from the 3.69 g of
nitrobenzene in this experiment. Give your answer to three significant figures.
Mr
: nitrobenzene,123; phenylamine, 93.1
IN QUESTION: Purification gave a 72.1% yield of phenylamine.
Do we use to percentage yield equation and rearrange after calculating moles of nitrobenzene? that's all that I can think of? Is it the wrong way of thinking?
I just wanna make sure I don't over complicate things
nitrobenzene in this experiment. Give your answer to three significant figures.
Mr
: nitrobenzene,123; phenylamine, 93.1
IN QUESTION: Purification gave a 72.1% yield of phenylamine.
Do we use to percentage yield equation and rearrange after calculating moles of nitrobenzene? that's all that I can think of? Is it the wrong way of thinking?
I just wanna make sure I don't over complicate things
1. calculate moles of limiting reagent
2. this gives moles of product
3. from 2 calculate theoretical mass
4. percentage yield = 100 * experimental mass/theoretical mass
Original post by charco
1. calculate moles of limiting reagent
2. this gives moles of product
3. from 2 calculate theoretical mass
4. percentage yield = 100 * experimental mass/theoretical mass
2. this gives moles of product
3. from 2 calculate theoretical mass
4. percentage yield = 100 * experimental mass/theoretical mass
I thought the percentage yield is already giving in the question? :/
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