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    http://pmt.physicsandmathstutor.com/...hapter%202.pdf
    Page 76. How would you know the line of symmetry is at x = 3/4 by simply drawing the graph? I would assume it would be x = 1 because that is the x value in my table of values with the lowest y value at y = -5. So you would assume that the minimum point is x = 1, so the line of symettery would be at x = 1.
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    (Original post by HumzaAhmed)
    http://pmt.physicsandmathstutor.com/...hapter%202.pdf
    Page 76. How would you know the line of symmetry is at x = 3/4 by simply drawing the graph? I would assume it would be x = 1 because that is the x value in my table of values with the lowest y value at y = -5. So you would assume that the minimum point is x = 1, so the line of symettery would be at x = 1.
    Don't do it from the graph and 'table of values'.

    At this level you should very well be able to complete the square on y=2x^2-3x-4 and read off the exact line of symmetry from that form.
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    (Original post by RDKGames)
    Don't do it from the graph and 'table of values'.

    At this level you should very well be able to complete the square on y=2x^2-3x-4 and read off the exact line of symmetry from that form.
    Yep that makes sense. Thank you. The question in the exercise and solutionbank answer are both misleading.
 
 
 
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