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    The nth term of a sequence is n^2+n
    Two consecutive terms in the sequence have a difference of 32.
    Work out the two terms.

    Thank you!!
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    Try factor out the nth term formula, what do you notice?
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    (Original post by Radioactivedecay)
    Try factor out the nth term formula, what do you notice?
    n(n+1)??
    I don't notice anything. 😱😱😱
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    n+1th term minus nth term set to 32 and solve.
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    (Original post by sweetstars)
    The nth term of a sequence is n^2+n
    Two consecutive terms in the sequence have a difference of 32.
    Work out the two terms.

    Thank you!!
    Two consecutive terms are n and n+1. We are looking for a pair so that the difference is 32. This means we can formulate [(n+1)^2 +(n+1)] - [n^2 + n] = 32
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    (Original post by sweetstars)
    n(n+1)??
    I don't notice anything. 😱😱😱
    It means that a term of a sequence is found by multiplying it by number right after it. Eg: the 7th term is found by multiplying 7 and 8. Can you now work out how to do it?
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    (Original post by RDKGames)
    Two consecutive terms are n and n+1. We are looking for a pair so that the difference is 32. This means we can formulate [(n+1)^2 +(n+1)] - [n^2 + n] = 32
    Aren't the contents of the first brackets multiplied instead of summed?
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    (Original post by Radioactivedecay)
    Aren't the contents of the first brackets multiplied instead of summed?
    Why would they be multiplied?
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    (Original post by RDKGames)
    Two consecutive terms are n and n+1. We are looking for a pair so that the difference is 32. This means we can formulate [(n+1)^2 +(n+1)] - [n^2 + n] = 32
    Also, Im pretty sure it should be (n+1)(n+2)-n (n+1)
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    (Original post by Radioactivedecay)
    Also, Im pretty sure it should be (n+1)(n+2)-n (n+1)
    Yes my LHS factorises to this.
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    (Original post by RDKGames)
    Why would they be multiplied?
    Nvm ignore me, you're right.
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    (Original post by Radioactivedecay)
    It means that a term of a sequence is found by multiplying it by number right after it. Eg: the 7th term is found by multiplying 7 and 8. Can you now work out how to do it?
    Please, another clue thank you. I don't get it...
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    (Original post by sweetstars)
    Please, another clue thank you. I don't get it...
    Have you tried what I said?
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    (Original post by Radioactivedecay)
    Nvm ignore me, you're right.
    Wait so which is the correct formula?
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    (Original post by sweetstars)
    The nth term of a sequence is n^2+n
    Two consecutive terms in the sequence have a difference of 32.
    Work out the two terms.

    Thank you!!
    let's say the first term if the two consecutive numbers is n. this means that's the next number is n+1.
    now since the difference is 32,we can say;
    nth term - (n+1)th term = 32
    And we r givene the formula to calculate the nth term of the sequence so;
    n (n+1) - (n+1)(n+1+1) = 32
    n(n+1)-(n+1)(n+2) = 32.
    Can u do it from here ?
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    (Original post by brainmaster)
    let's say the first term if the two consecutive numbers is n. this means that's the next number is n+1.
    now since the difference is 32,we can say;
    nth term - (n+1)th term = 32
    And we r givene the formula to calculate the nth term of the sequence so;
    n (n+1) - (n+1)(n+1+1) = 32
    n(n+1)-(n+1)(n+2) = 32.
    Can u do it from here ?
    You mean (n+1)th term minus nth term, not other way around
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    (Original post by RDKGames)
    Have you tried what I said?
    Is it 15 and 16?
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    (Original post by sweetstars)
    Is it 15 and 16?
    Yep.
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    (Original post by RDKGames)
    Yep.
    Thank you very much!
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    (Original post by RichE)
    You mean (n+1)th term minus nth term, not other way around
    yes thanks for that.
    however we could also use nth term - (n+1)th term = 32
    but u get n as -15 and we know n can never be a negative hence u ignore the negative.
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