So my maths teacher gave me this question at the end of school today and I told him that I would get it done for tomorrow. He is currently "one over on me" so I really want to get the answer back to him so we are even and I have the last laugh. However, the question he gave me has seriously perplexed me and I do not know what to do.
I worked out that bh=r^2 so the area of the triangle is r^2/2 and the area of the circle is pi r^2. But this has taken me nowhere...
Any suggestions?
Thanks in advance
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Y11_Maths
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- 12-03-2018 21:24
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Notnek
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- 12-03-2018 21:55
Hmm the challenge is to do this without using A Level methods...
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Y11_Maths
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- 12-03-2018 21:56
(Original post by Notnek)
Hmm the challenge is to do this without using A Level methods...Posted on the TSR App. Download from Apple or Google Play -
Radioactivedecay
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- 12-03-2018 21:59
(Original post by Y11_Maths)
So is this a GCSE question? -
Y11_Maths
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- 12-03-2018 22:00
(Original post by Radioactivedecay)
This is definitely doable for GCSE students, but it requires some thought.Posted on the TSR App. Download from Apple or Google Play -
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- 12-03-2018 22:02
I'm attempting it...
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Radioactivedecay
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- 12-03-2018 22:06
(Original post by Y11_Maths)
Help, please? -
psc---maths
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- 12-03-2018 22:09
Find the area of the two smaller triangles in terms of x using 1/2absinc then find triangle/circle and equate this to 1/2pi. Reminder that sin(180-2x)=sin(2x): think about the graph of sin!Posted on the TSR App. Download from Apple or Google PlayLast edited by psc---maths; 12-03-2018 at 22:10. Reason: TDA Post Edit -
I hate maths
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- 12-03-2018 22:09
(Original post by Notnek)
Hmm the challenge is to do this without using A Level methods...
My gripe with the question is that it doesn't specify angle BAC is less than CBA, so BAC could be 75 instead. -
Radioactivedecay
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- 12-03-2018 22:11
(Original post by psc---maths)
Find the area of the two smaller triangles in terms of x using 1/2absinc then find triangle/circle and equate this to 1/2pi. Reminder that sin(180-2x)=sin(2x): think about the graph of sin! -
Notnek
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- 12-03-2018 22:13
(Original post by I hate maths)
Which bit in your work did you need A Level maths? If you did something similar to me, you don't actually need to simplify the trig with A Level identities but you could just sub the answer given in to confirm it's the solution. -
Y11_Maths
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- 12-03-2018 22:14
(Original post by psc---maths)
Find the area of the two smaller triangles in terms of x using 1/2absinc then find triangle/circle and equate this to 1/2pi. Reminder that sin(180-2x)=sin(2x): think about the graph of sin!Posted on the TSR App. Download from Apple or Google Play -
psc---maths
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- 12-03-2018 22:15
(Original post by Y11_Maths)
The height isn’t r though?Posted on the TSR App. Download from Apple or Google Play -
psc---maths
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- 12-03-2018 22:17
(Original post by psc---maths)
It isn't meant to be the height. It is the line drawn from the centre to B, so it is a radius of length rPosted on the TSR App. Download from Apple or Google Play -
Radioactivedecay
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- 12-03-2018 22:20
(Original post by Y11_Maths)
The height isn’t r though? -
I hate maths
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- 12-03-2018 22:20
(Original post by Radioactivedecay)
I don't think that diagram is correct. -
psc---maths
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- 12-03-2018 22:23
(Original post by I hate maths)
I think it is correct but the original triangle is easy enough to work with without splitting.Posted on the TSR App. Download from Apple or Google Play -
Y11_Maths
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- 12-03-2018 22:25
(Original post by psc---maths)
Find the area of the two smaller triangles in terms of x using 1/2absinc then find triangle/circle and equate this to 1/2pi. Reminder that sin(180-2x)=sin(2x): think about the graph of sin!Posted on the TSR App. Download from Apple or Google Play -
Y11_Maths
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- 12-03-2018 22:27
(Original post by Radioactivedecay)
Disregard my earlier comment. An easier way would be find the other two sides of the triangle in terms of r and x using SOCAHTOA, and then finding the area of the triangle from there.Posted on the TSR App. Download from Apple or Google Play -
I hate maths
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- 12-03-2018 22:28
(Original post by psc---maths)
Wrt the other way would that not require 2sinxcosx=sin2x. I was giving a gcse level answer
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