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    Can someone differentiate \ 2^{-1/2} * x^{3/2} with workings please! cheerio
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    (Original post by ᒍack)
    Can someone differentiate \ 2^{1/2} * x^{3/2} with workings please! cheerio
    What have you done so far? We're not allowed to provide answers. Assuming that the 2^{0.5} is just a prefactor, this should be quite straightforward.
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    (Original post by ᒍack)
    Can someone differentiate \ 2^{1/2} * x^{3/2} with workings please! cheerio
    You try it and we'll help - we don't do questions for you.
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    (Original post by Muttley79)
    You try it and we'll help - we don't do questions for you.
    I tried it in another thread been trying to find out what to do for an hour and still at the same point, just want someone to show workings so i can see what i'm doing wrong
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    (Original post by ᒍack)
    I tried it in another thread been trying to find out what to do for an hour and still at the same point, just want someone to show workings so i can see what i'm doing wrong
    How would you differentiate x^{\frac{3}{2}}? It's just that, but multiplied by \sqrt{2}.
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    before any help, perhaps share your thought process when looking at the question. What is it exactly that you are having a hard time with.
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    Multiply the x coefficient (root 2) by the exponent, and simply decrease the exponent by 1.
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    (Original post by ᒍack)
    I tried it in another thread been trying to find out what to do for an hour and still at the same point, just want someone to show workings so i can see what i'm doing wrong
    What is the rule for differentiating ax^n?
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    (Original post by RedGiant)
    Multiply the x coefficient (root 2) by the exponent, and simply decrease the exponent by 1. Root 2 is simply a constant.
    Thank you
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    (Original post by Muttley79)
    What is the rule for differentiating ax^n?
    anx^n-1
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    Oops, I meant to put \ 2^{-1/2} * x^{3/2}
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    again just take the 2^-1/2 as a constant and multiply it by the derivative of x^3/2 you can then do some tidying up of the answer if you want I don't know if im supposed to send a pic of the full solution or not
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    (Original post by ruhplus)
    again just take the 2^-1/2 as a constant and multiply it by the derivative of x^3/2 you can then do some tidying up of the answer if you want I don't know if im supposed to send a pic of the full solution or not
    I ended up doing \ 1/2^{-1/2} * 3/2 then doing \ x^{1/2} * 3 then cleaning it up to give \ 3/2*x^{1/2}/2^{1/2}
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    Rather simple. Root of 2 is a constant so the basic power rule is enough.
    Posted on the TSR App. Download from Apple or Google Play
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    (Original post by ᒍack)
    I ended up doing \ 1/2^{-1/2} * 3/2 then doing \ x^{1/2} * 3 then cleaning it up to give \ 3/2*x^{1/2}/2^{1/2}
    right so, firstly I think you made a typo as its \ 1/2^{1/2} not a negative 1/2, as having 1 over a negative power makes a positive one. Also, why did you do \ x^{1/2} * 3 ?
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    (Original post by ruhplus)
    right so, firstly I think you made a typo as its \ 1/2^{1/2} not a negative 1/2, as having 1 over a negative power makes a positive one. Also, why did you do \ x^{1/2} * 3 ?
    Yeah it's meant to be ^-1/2
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    (Original post by ruhplus)
    right so, firstly I think you made a typo as its \ 1/2^{1/2} not a negative 1/2, as having 1 over a negative power makes a positive one. Also, why did you do \ x^{1/2} * 3 ?
    Ahhh.. i see what people mean now.. I didn't know I could just keep the constant and take the derivative of the rest of the term then multiply... my book didn't even mention it... ughh.... tgwerhbwtehiuoqwerhgfw3hrgbw4rhb w45thwrthw45thw4thw4thmndtyj erythje6t4r4r4r4r4r4rytrey

    Thanks everyone..
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    (Original post by ᒍack)
    Yeah it's meant to be ^-1/2
    yeah but \ 1/2^{1/2} is the same as \ 2^{-1/2} so I'm just saying that you kind of did a maths equivalent of a double negative. Your answer is almost right but as I implied in the last message you shouldn't have multiplied by just a 3.
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    (Original post by ᒍack)
    Ahhh.. i see what people mean now.. I didn't know I could just keep the constant and take the derivative of the rest of the term then multiply... my book didn't even mention it... ughh.... tgwerhbwtehiuoqwerhgfw3hrgbw4rhb w45thwrthw45thw4thw4thmndtyj erythje6t4r4r4r4r4r4rytrey

    Thanks everyone..
    good, so you've managed to get the right answer now?
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    (Original post by ruhplus)
    good, so you've managed to get the right answer now?
    Yeah the answer is still the same 3/2 * x / 2
 
 
 
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