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    Attachment 730980

    i) Was good, I got t = (1-x)/x
    ii) Was good
    iii) I found the y-coordinate as y = 1/(1-t)

    question iv) The point Q is the intersection of the line x = 1/2 and the straight line joining the origin to the point T. Point R has co-ordinates (1/2, 0). Show that RQ = QP.

    I am completely stuck on how to do this question.
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    (Original post by znx)

    i) Was good, I got t = (1-x)/x
    ii) Was good
    iii) I found the y-coordinate as y = 1/(1-t)

    question iv) The point Q is the intersection of the line x = 1/2 and the straight line joining the origin to the point T. Point R has co-ordinates (1/2, 0). Show that RQ = QP.

    I am completely stuck on how to do this question.
    Post a better quality image on https://imgur.com/ then post the link here.

    The current image is impossible to read.
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    (Original post by RDKGames)
    Post a better quality image on https://imgur.com/ then post the link here.

    The current image is impossible to read.
    Yeah sorry for that should be better now.
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    (Original post by znx)
    Yeah sorry for that should be better now.
    This question was asked before: https://www.thestudentroom.co.uk/sho...php?p=75995584
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    (Original post by RDKGames)
    This question was asked before: https://www.thestudentroom.co.uk/sho...php?p=75995584
    ah ok thank you
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    (Original post by RDKGames)
    This question was asked before: https://www.thestudentroom.co.uk/sho...php?p=75995584
    Thus, the gradient OT is given by , - I thought from ii) that the gradient m is found by dy/dx = -2t/(1-t)^2 ?
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    (Original post by znx)
    Thus, the gradient OT is given by , - I thought from ii) that the gradient m is found by dy/dx = -2t/(1-t)^2 ?
    Yeah that's the gradient along the curve.

    OT is not along the curve.
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    (Original post by RDKGames)
    Yeah that's the gradient along the curve.

    OT is not along the curve.
    I've still been struggling on the question, I used , and hence the line is
    When x = 1/2 I plugged that into the parametric equation to find what t was at the point, however t cant be +/- 1. So I dont really know what to do tbh.
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    (Original post by znx)
    I've still been struggling on the question, I used , and hence the line is
    When x = 1/2 I plugged that into the parametric equation to find what t was at the point, however t cant be +/- 1. So I dont really know what to do tbh.
    When x=1/2, what is y in terms of t?

    Then you know the coordinates of the point Q in terms of t. You also know the coords of R and P. So show that the distances RQ = QP
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    (Original post by RDKGames)
    When x=1/2, what is y in terms of t?

    Then you know the coordinates of the point Q in terms of t. You also know the coords of R and P. So show that the distances RQ = QP
    So i just sub x =1/2 into that equation for the line?
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    (Original post by znx)
    So i just sub x =1/2 into that equation for the line?
    Well, yeah.
 
 
 
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