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    Do electrical circuit components have + and - terminals just like a battery or cell? And if so how do you determine which is which?
    And does connecting the component the other way round cause the current and pd to become - ?
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    (Original post by G.Y)
    Do electrical circuit components have + and - terminals just like a battery or cell? And if so how do you determine which is which?
    And does connecting the component the other way round cause the current and pd to become - ?
    Only some components depend on being connected in a specific direction, such as diodes and LEDS, and some capacitors.

    Connecting the component the other way doesn't change the current and p.d. That only happens when you flip the battery/cell around
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    (Original post by G.Y)
    Do electrical circuit components have + and - terminals just like a battery or cell? And if so how do you determine which is which?
    And does connecting the component the other way round cause the current and pd to become - ?
    Some electric components like the LEDs, electrolytic capacitors and diodes are polarised.This means that if they are plugged in the wrong way, they will break or they will just not let current flow though it.There are markings on these components which indicate which terminal is negave/positive.

    However, not all components are polarised. These include resistors, variable resistors (e.g LDR and thermistor), switches, light bulbs, etc...
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    (Original post by stoyfan)
    Some electric components like the LEDs, electrolytic capacitors and diodes are polarised.This means that if they are plugged in the wrong way, they will break or they will just not let current flow though it.There are markings on these components which indicate which terminal is negave/positive.

    However, not all components are polarised. These include resistors, variable resistors (e.g LDR and thermistor), switches, light bulbs, etc...
    So these components with terminals do cause current and pd to become minus? If you look at the IV graph for a diode it's basically flat in the - quadrant which occurs when it's connected in reverse?
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    (Original post by G.Y)
    So these components with terminals do cause current and pd to become minus? If you look at the IV graph for a diode it's basically flat in the - quadrant which occurs when it's connected in reverse?
    No, it depends on the component.

    A diode only allows for current to flow one way, which is evident in your I-V graph as it is flat with a gradient of 0 in the - quadrant.

    In the +quadrant, the gradient should be higher than 0.
 
 
 
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