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1. A curve has equation , show that the curve cuts the x-axis at the point where x=a, with 1<a<ln3

Any help?
2. I would sub in 1 and ln3 into the eqn and point out that one point is above the x axis and the other is below it
3. (Original post by Edgemaster)
I would sub in 1 and ln3 into the eqn and point out that one point is above the x axis and the other is below it
Damn, Im so dumb. Thank you very very much
4. (Original post by Edgemaster)
I would sub in 1 and ln3 into the eqn and point out that one point is above the x axis and the other is below it
Do you by any chance know how to do this question?

Curve C has equation
Show that the x-coordinate of any stationary point of C satisfies the equation.

Never mind I know what to do, I think

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