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# Another Parametric Problem watch

1. Find the equation of the normal to the curve:
x=t^2
y=t+1/t
at the point on the curve where t=2

So far I've got dy/dx = 1+2t^3 but I feel this is wrong
2. Dy/dx = (dy/dt)÷ (dx/dt)

What are you getting for your dervatives ?
3. (Original post by NotNotBatman)
Dy/dx = (dy/dt)÷ (dx/dt)

What are you getting for your dervatives ?
dx/dt = 2t
dy/dt = 1 - 1/t^2
4. (Original post by TehJokur)
dx/dt = 2t
dy/dt = 1 - 1/t^2
Correct so dy/dx is

Note i am multiplying by 1 in the form t^2/t^2 to get rid of the triple fraction.
5. (Original post by NotNotBatman)
Correct so dy/dx is

Note i am multiplying by 1 in the form t^2/t^2 to get rid of the triple fraction.
How did the 2t come to be dividing the 1 - 1/t^2?
6. Anyone?
7. (Original post by TehJokur)
How did the 2t come to be dividing the 1 - 1/t^2?

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