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Maths edexcel vector question
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Dm998
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Question lifted from past edexcel paper .
OAN OMB and APB are straight lines. M is the midpoint of OB.
OA=a. Vector
OB=b. Vector.
AP(vector)=k x AB(vector) where k is a scalar quantity.
Given that MPN is a straight line find the value of k
Thanks
OAN OMB and APB are straight lines. M is the midpoint of OB.
OA=a. Vector
OB=b. Vector.
AP(vector)=k x AB(vector) where k is a scalar quantity.
Given that MPN is a straight line find the value of k
Thanks
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ada_786
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Dm998
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Toki the Dumdum
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#4
(Original post by Dm998)
Question lifted from past edexcel paper .
OAN OMB and APB are straight lines. M is the midpoint of OB.
OA=a. Vector
OB=b. Vector.
AP(vector)=k x AB(vector) where k is a scalar quantity.
Given that MPN is a straight line find the value of k
Thanks
Question lifted from past edexcel paper .
OAN OMB and APB are straight lines. M is the midpoint of OB.
OA=a. Vector
OB=b. Vector.
AP(vector)=k x AB(vector) where k is a scalar quantity.
Given that MPN is a straight line find the value of k
Thanks
Also, you have to post what you've worked out/tried so far before people can help you.
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ada_786
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Dm998
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I'll add the question and working out if someone can tell me how to add an attachment
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Toki the Dumdum
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#7
(Original post by Dm998)
I'll add the question and working out if someone can tell me how to add an attachment
I'll add the question and working out if someone can tell me how to add an attachment
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Dm998
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Dm998
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#9
(Original post by ada_786)
The answer is 2/5 but I keep getting -5/2
The answer is 2/5 but I keep getting -5/2
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ada_786
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Toki the Dumdum
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#11
(Original post by Dm998)
Not on my screen
Not on my screen
https://imgur.com/b7PDxSM
This is the question? (you left out AN=2OA in your original post).
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Dm998
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Y2_UniMaths
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#13
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#13
This questions has already been answered in a different thread https://www.thestudentroom.co.uk/sho....php?t=5262824
You can thank ghostwalker
You can thank ghostwalker
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doctorwhonerd42
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#14
AB=b-a
MN=-0.5b+a+3a
MN=4a-0.5b
MP=-0.5b+a+k(b-a)
MP=-0.5b+a+kb-ka
4/1-k=-0.5/-0.5+k (number of As in MN divided by As in MP = no. Bs in MN/Bs in MP)
8/2-2k=-1/-1+2k
8(-1+2k)=-1(2-2k)
-8+16k=-2+2k
14k=6
k=6/14
k=3/7
Hope that helps
MN=-0.5b+a+3a
MN=4a-0.5b
MP=-0.5b+a+k(b-a)
MP=-0.5b+a+kb-ka
4/1-k=-0.5/-0.5+k (number of As in MN divided by As in MP = no. Bs in MN/Bs in MP)
8/2-2k=-1/-1+2k
8(-1+2k)=-1(2-2k)
-8+16k=-2+2k
14k=6
k=6/14
k=3/7
Hope that helps
Last edited by doctorwhonerd42; 3 years ago
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Pro student
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#15
AB = AO+OB
AB = -a+b
MN = MO+OA+AN
MN = -0.5b+a+2a
MN = 3a-0.5b
MP = MO+OA+AP
MP = -0.5B+a-ka+kb
NM = -3a+0.5b
NP = -2a+k(-a+b)
NPM is a straight line, so,
x × NP = NM
k = 2/5
Little late but correct
AB = -a+b
MN = MO+OA+AN
MN = -0.5b+a+2a
MN = 3a-0.5b
MP = MO+OA+AP
MP = -0.5B+a-ka+kb
NM = -3a+0.5b
NP = -2a+k(-a+b)
NPM is a straight line, so,
x × NP = NM
k = 2/5
Little late but correct
Last edited by Pro student; 2 years ago
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mahrunnasa
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#16
(Original post by Pro student)
AB = AO+OB
AB = -a+b
MN = MO+OA+AN
MN = -0.5b+a+2a
MN = 3a-0.5b
MP = MO+OA+AP
MP = -0.5B+a-ka+kb
NM = -3a+0.5b
NP = -2a+k(-a+b)
NPM is a straight line, so,
x × NP = NM
k = 2/5
Little late but correct
AB = AO+OB
AB = -a+b
MN = MO+OA+AN
MN = -0.5b+a+2a
MN = 3a-0.5b
MP = MO+OA+AP
MP = -0.5B+a-ka+kb
NM = -3a+0.5b
NP = -2a+k(-a+b)
NPM is a straight line, so,
x × NP = NM
k = 2/5
Little late but correct
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