amino acids polymers chem question help
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Lia22
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part b
I have no idea what I'm doing, any guidance would be appreciated thanks
I have no idea what I'm doing, any guidance would be appreciated thanks
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username3718068
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(Original post by Lia22)
part b
I have no idea what I'm doing, any guidance would be appreciated thanks
part b
I have no idea what I'm doing, any guidance would be appreciated thanks
Well E contains an aldehyde functional group because it is oxidised to a carboxylic acid F by Tollens reagent.
So we can say E is (so far) : C3H6N-CHO
if we end up with alpha amino acid F (oxidised version of E) and we know that general formula of amino acid is NH2 CH(R) COOH
then F is NH2 CH(C2H3)COOH where R = C2H3 (hopefully this will you figure that C2H3 is just ethene minus a hydrogen atom because in place of that hydrogen you have the alpha carbon of the amino acid).
so I'd say this is E:
NH2CH(C2H3)CHO
(notice this can exist as a pair of enantiomers)
and this is F:
NH2CH(C2H3)COOH
Now F can form 2 different polymers which are condensation polymers and addition polymers. This is because with addition polymers we have the double bond in the side chain (C2H3) so in that sense F can form addition polymers.
F can also form condensation polymer (carboxylic acid group and primary amine group forming the N substituted amide).
Considering that the differences in compound G and H:
* compound H has one less O and two less Hydrogen than compound G (= water has left in the polymerisation in one of them)
you should be able to figure out the repeating units for G and H. Hence you should be able to be able to figure out their reaction pathway
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