a= oxidation state is +3 I don't know how we are supposed to work on b as I don't know what oxidation state of C for c = I think oxidation state is -1 for d= oxidation state is +1
a= oxidation state is +3 I don't know how we are supposed to work on b as I don't know what oxidation state of C for c = I think oxidation state is -1 for d= oxidation state is +1
for a) oxidation state of V is +3 as you said
for b) what is the charge of an ethanedioate ion? Then its a matter of solving an equation: V + (3 * charge of ethanedioate ) = +3
for c) charge of OH group? then solve another equation: V + (3 * charge of OH ligand) = 0
for d) charge of chloride ligand? V + (4 * charge of chloride ligand ) = -3
a= oxidation state is +3 I don't know how we are supposed to work on b as I don't know what oxidation state of C for c = I think oxidation state is -1 for d= oxidation state is +1
no oxidation state is +3 on a b and c but for d it is +1