integrate

∫ 2tanx/tan2x

1) changed it and i got ∫ 1-(tanx)^2
2)??????

by the way is∫tan2x = (sec2x)^2

∫ 2tanx/tan2x

by the way is∫tan2x = (sec2x)^2

no you are thinking of the derivative of tan.

to integrate it think of writing it as sinx/cosx and how to integrate a fraction.

Write tan^2x in terms of secx and integrate from there.

∫ 2tanx/tan2x

1) changed it and i got ∫ 1-(tanx)^2
2)??????

Note that

\tan^2 x = \sec^2x -1

by the way is∫tan2x = (sec2x)^2

No, it's

\frac{1}{2}\log | \sec 2x | + c

∫ 2tanx/tan2x

1) changed it and i got ∫ 1-(tanx)^2
2)??????

by the way is∫tan2x = (sec2x)^2

Try using the identity for 1 + tan^2(x). sec^2(x) is much easier to integrate than tan^2(x) is.

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