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C4 Parametric Equation

How do you find the cartesian equation of
x = t/(1+t) and y=t/(1-t)?
(edited 6 years ago)

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Original post by 123456123456
How do you find the cartesian equation of
x = t/(1+t) and y=t(1-t)?


By eliminating tt

Have you tried anything??
I have tried multiplying them, subtracting them and adding them but nothing working so far - can you help?
Original post by RDKGames
By eliminating tt


lol I bet this must have been really helpful to him 😆😆😆
Original post by 123456123456
I have tried multiplying them, subtracting them and adding them but nothing working so far - can you help?


how about squaring them then adding?
How do you find the cartesian equation of
x = t/(1+t) and y=t(1-t)?

I have been trying addition, subtraction, squaring, and multiplying and nothing seems to be worked.

A worked solution if you can solve it would be much appreciated
Original post by brainmaster
how about squaring them then adding?


I have had a go myself doing this and not getting there. If you have done it this way and it worked, would you mind posting a worked solution?
Thank you - been stuck on this for ages now
How do you find the cartesian equation of
x = t/(1+t) and y=t/(1-t)?

I have been trying lots of different methods and nothing seems to be working. A worked solution would be much appreciated if you can solve it. Thank you.
Reply 8
Original post by 123456123456
How do you find the cartesian equation of
x = t/(1+t) and y=t(1-t)?

I have been trying addition, subtraction, squaring, and multiplying and nothing seems to be worked.

A worked solution if you can solve it would be much appreciated


Get t in terms of x.

Sub into ur equation for y.
Just realised the question should be

x = t/(1+t) and y=t/(1-t)?

I missed off the divide from the y=

Still stuck with this question if you can help
Reply 10
Original post by 123456123456
I have tried multiplying them, subtracting them and adding them but nothing working so far - can you help?

Just checking : did you post the question correctly? It's not y=t/(1-t) is it?
Original post by Notnek
Just checking : did you post the question correctly? It's not y=t/(1-t) is it?


Yes just realised that I had made this mistake - i have editted now. Can you solve it and post a worked solution?
Reply 12
Original post by 123456123456
Yes just realised that I had made this mistake - i have editted now. Can you solve it and post a worked solution?

There are different ways to do this. Try considering the reciprocals of the fractions i.e. 1/x and 1/y. Post your working if you get stuck.
Find t as a function of x and then substitute into your y
Original post by Notnek
There are different ways to do this. Try considering the reciprocals of the fractions i.e. 1/x and 1/y. Post your working if you get stuck.


Thanks so much have solved it now
Reply 15
Original post by 123456123456
Thanks so much have solved it now

Also, a standard method that works a lot of the time (and others mentioned it above) is to make t the subject and then sub it in to the other equation. I recommend trying this method here so you get practice.
Original post by 123456123456
Thanks so much have solved it now


Can you post the solution please?
Original post by thekidwhogames
Find t as a function of x and then substitute into your y


More often than not there are much more elegant ways to deal with these questions than brute force which may not always work anyway.
Original post by frankabagnale
Can you post the solution please?


1/y = (1-t)/t
1/x = t/(1+t)

1/y - 1/x = -2

1/y = 1/x -2

x = y-2xy
x=y(1-2x)

x/(1-2x) = y
Original post by 123456123456
1/y = (1-t)/t
1/x = t/(1+t)

1/y - 1/x = -2

1/y = 1/x -2

x = y-2xy
x=y(1-2x)

x/(1-2x) = y


Thanks! I came out with y=x+2xy by going the long way. Anyone know if its okay to leave my answer like that?

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