NH Second Order Differential Equation
Because I got equal roots from the auxiliary equation my complimentary function is y=Ae^3x + Bxe^3x
The function equal to the differential equation is 4e^3x, I can't use Pe^3x or Pxe^3x as they both appear in the complimentary function. Do I use x^2?
The function equal to the differential equation is 4e^3x, I can't use Pe^3x or Pxe^3x as they both appear in the complimentary function. Do I use x^2?
Original post by Consectatrix
Because I got equal roots from the auxiliary equation my complimentary function is y=Ae^3x + Bxe^3x
The function equal to the differential equation is 4e^3x, I can't use Pe^3x or Pxe^3x as they both appear in the complimentary function. Do I use x^2?
The function equal to the differential equation is 4e^3x, I can't use Pe^3x or Pxe^3x as they both appear in the complimentary function. Do I use x^2?
Yep
nice, thanks
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