# help with mathsWatch

#1

how do i find the value of u?
0
11 months ago
#2
Area under the graph = 200m, so find all the areas of the simple shapes, add them together and equate to 200m, and you should find u
0
#3
(Original post by Johnlock93)
Area under the graph = 200m, so find all the areas of the simple shapes, add them together and equate to 200m, and you should find u
i didnt think of this, thank you
0
11 months ago
#4
The total area under the graph is 200metres. Work out the total area under the graph in terms of u and form an equation then solve for u.
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#5
(Original post by Y11_Maths)
The total area under the graph is 200metres. Work out the total area under the graph in terms of u and form an equation then solve for u.
i think ive done it wrong
0
11 months ago
#6
(Original post by chloesky2018)
i think ive done it wrong
0
#7
(Original post by Y11_Maths)
its deffo wrong
0
11 months ago
#8
(Original post by chloesky2018)
its deffo wrong
Ok we can make this simpler. We know in the first 20 seconds he ran 162m. So 200-162=38m. So the final segment area must equal 38. It’s a trapezium so use the formula 1/2(a+b)h and substitute your values in and set equal to 38. Can you take it from here?
0
#9
(Original post by Y11_Maths)
Ok we can make this simpler. We know in the first 20 seconds he ran 162m. So 200-162=38m. So the final segment area must equal 38. It’s a trapezium so use the formula 1/2(a+b)h and substitute your values in and set equal to 38. Can you take it from here?
so far i have gotten to 22.5U for the final segment, thats the area, what do i do next?
0
#10
(Original post by Y11_Maths)
Ok we can make this simpler. We know in the first 20 seconds he ran 162m. So 200-162=38m. So the final segment area must equal 38. It’s a trapezium so use the formula 1/2(a+b)h and substitute your values in and set equal to 38. Can you take it from here?
this is the answer but i dont really understand it
0
#11
its okay ive solved it now thank you
0
11 months ago
#12
I recognise that problem!

Gave it to my Year 12 Core Maths set a couple of weeks ago ...
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#13
(Original post by DoNotDivideBy0)
I recognise that problem!

Gave it to my Year 12 Core Maths set a couple of weeks ago ...
year 12? so this is basically a-level maths im doing?
0
11 months ago
#14
No ... Core Maths (also known as Functional Maths) is the qualification offered to those who passed their GCSE but not with top grades, and wish to continue studying maths but not to take the A level course.
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#15
(Original post by DoNotDivideBy0)
No ... Core Maths (also known as Functional Maths) is the qualification offered to those who passed their GCSE but not with top grades, and wish to continue studying maths but not to take the A level course.
but wouldnt this be the basic foundation for a-level maths since its apparently a grade 9 topic and has come down from a-levels into gcse
0
11 months ago
#16
(Original post by chloesky2018)
but wouldnt this be the basic foundation for a-level maths since its apparently a grade 9 topic and has come down from a-levels into gcse
This is not grade 9 or anywhere near to A-Level. This is probably a grade 6 Question
0
#17
(Original post by Y11_Maths)
This is not grade 9 or anywhere near to A-Level. This is probably a grade 6 Question
seriously? so what teachers told me were bs
so how am i supposed to get a 9 then
0
11 months ago
#18
(Original post by chloesky2018)
seriously? so what teachers told me were bs
so how am i supposed to get a 9 then
I thought you were several months behind in your subjects anyways?
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#19
(Original post by Y11_Maths)
I thought you were several months behind in your subjects anyways?
i am
0
11 months ago
#20
Yes. To answer a question such as this you've got to understand the key points about velocity / time graphs (namely that the gradient gives you the acceleration, and the area under the graph gives you the distance travelled), to reason forward and backwards, apply a variety of geometrical area formulas ... it's quite a complicated question.

My Year 12s didn't do it at all well, and I'm going to be going over it all again with them after Easter.
0
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