Hi,
I was wondering if anyone could help explain to me the difference in reactivity between an aldehyde and a ketone when heated under reflux with acidified potassium dichromate (K2Cr2O7/H+).
I understand the basic principles of the reaction:
Where by the aldehyde is oxidised by the potassium dichromate which is reduced, to produce the carboxylic acid (propanoic acid) turning the orange solution to green.
And that the Ketone can not be further oxidised and therefore remains orange.
But I don't understand how the mechanism actually takes place?
What actually happens to the aldehyde to become oxidised? is it through the loss of the hydrogen from the carbonyl group (C=O)?.
And if so, where does it go?
I've looked at several contradicting sources and the best answer I can find is that the Ketone can not be further oxidised due to the 'lack of oxygen' and that the aldehyde can be due to the contrary?
But that isn't enough for me to understand the reaction.
So if anyone can help me, I'd greatly appreciate it